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How to write python list comprehension without tolist() or list()?
Is there a way to write list comprehension with operator not involving tolist() (list() also returns a list)?
For example:
>>> l = [1,2,3,4,5,6]
>>> [i+1 for i in l if i%3==0]
[3, 6, 9]
I want to get this output without tolist() (only list(), and no tolist, is that possible?)
A:
It is not possible to avoid tolist() in list comprehension, as it is list comprehension itself.
>>> [i+1 for i in l if i%3==0]
[3, 6, 9]
>>> l
[1, 2, 3, 4, 5, 6]
>>> [i+1 for i in l if i%3==0] is l
True
On the other hand, you may want to consider using filter(), map() or even reduce() function. map() is similar to list comprehension when your list is homogenous, for example:
>>> filter(lambda x: x%3==0, l)
[3, 6, 9]
or even more on the functional side with reduce():
>>> reduce(lambda x, y: x+y, l, [])
[3, 6, 9]
p53 expression in mononuclear cells predicts outcome in patients with small cell lung cancer.
The role of the p53 tumour suppressor gene in the pathogenesis and prognosis of small cell lung cancer (SCLC) is incompletely understood. We examined p53 expression by immunocytochemistry in 794 paraffin-embedded neoplastic, adjacent normal and metastatic lymph node tissues from 48 consecutive patients with S
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