Vijeo Designer 6.1 SP2

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There are two things that you might want to check:
The 6.1 maintenance was only released in February 2016, so this is probably the issue.
The documentation lists only the data collection for Version 6.1 SP2. If you need a second configuration, then you might need to open a ticket with the support team of your vendor.
Q:
Iterating over a Python list without using 'for'
I had this question on an interview test and was asked to solve it using only list comprehension.
My solution was:
[x for x in range(0, 10) if x + 1 == 2*x]
The correct answer was [0, 4, 7].
Now I would like to know if the answer was correct, I would like to know if the following solution is true:
[x for x in range(0, 10) if x + 1 == 2*x]
A:
Let's understand what is happening here:
If we have our list
>>> x = [1,2,3,4,5]
now we iterate over our list and perform the following operation each time:
>>> x[0]
1
>>> x[0] + 1
2
and so on...
[x for x in range(0, 10) if x + 1 == 2*x]
^ ^
will now run a for loop over each of the items of our list
We are defining a new variable x each time our loop runs. This is why your solution is incorrect.
You would have to do this:
>>> y = [x for x in range(0, 10) if x + 1 == 2*x]
or without for loops
>>> [x for x in range(0, 10) if x + 1 == 2*x]
[0, 4, 7]
in your case this is probably best explained with a graph:
If we see this as a graph, we will see that our new x variable is not a list comprehension, but a for loop.
As a side note, if you are interested in generating a list based on some fact, you can use the following with list comprehensions:
>>> def f(x):
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